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Question

For the reversible isothermal expansion of one mole of an ideal gas at 300 K, from the volume of 10 dm3 to 20 dm3,ΔH is:

A
5.73 kJ
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B
1.73 kJ
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C
3.46 kJ
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D
Zero
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Solution

The correct option is C 1.73 kJ
Solution:-
Work done in an isothermal reversible process is given by-
W=nRTlnV2V1
Where,
n = no. of moles =1
R= molar gas constant =8.314Jmol1K1
T= temperature =300K
V1=10dm3
V2=20dm3
W=1×8.314×300×ln2010
W=2494.2×(ln2ln1)=1728.8 J=1.73 kJ

Now, from first law of thermodynamics,
ΔU=ΔH+W

Since temperature is constant, i.e. ΔU=0.
ΔH=W=(1.73)=+1.73KJ

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