For the reversible reaction, if a concentration of reactants are doubled at a definite temperature, then the value of equilibrium constant will:

be reduced to half

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be reduced to one fourth

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also be doubled

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remains constant

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Solution

The correct option is D remains constant
Doubling the initial concentrations of reactants in an equilibrium does not result in change in $K_{c}$ value. $K_{c}$ remains the same at a particular temperature.

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