For the same statement as above, the ratio of the two image sizes for these two positions of the lens is

True

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False

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Solution

The correct option is B False
$u + v = d$
$u_{1} = \frac{D + \sqrt{D (D - 4 f)}}{2}$ and $u_{2} = \frac{D - \sqrt{D (D - 4 f)}}{2}$
$u_{1} = \frac{D + d}{2}$ and $u_{2} = \frac{D - d}{2}$
$v_{1} = D - u_{1} = \frac{D - d}{2}$ and $v_{2} = \frac{D + d}{2}$
ratio of magnifications is $\frac{(D + d)^{2}}{(D - d)^{2}}$
option $B$ is correct

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For the same statement as above, the ratio of the two image sizes for these two positions of the lens is

The correct option is B Falseu+v=du1=D+√D(D−4f)2 and u2=D−√D(D−4f)2u1=D+d2 and u2=D−d2v1=D−u1=D−d2 and v2=D+d2ratio of magnifications is (D+d)2(D−d)2option B is correct