For the sequence of reactions, (given) tert-Pentyl alcohol. The compound A in the sequence is:

2-Butanone

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Acetaldehyde

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Acetone

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Propanal

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Solution

The correct option is C Acetone
This is an example of grignards reaction.In this reaction the reactant A is made to react with ethyl magnesium iodine in ether solution which on hydrolysis gives pentyl alcohol.Therefore at the place where $O H$ group is present in product,a carbonyl group would have been present in reactant and also ethyl would have been added at that same C from $C_{2} H_{5} M g I$ .Thus the reactant would have been acetone.

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C H_{3} C H_{2} C H_{2} O H P C l_{5} - -- \to A a l c o h o l i c - ---- \to K O H

T e r t -

E t O H - -- \to H I - - \to

C H_{3} C H_{2} C H_{2} O H P C l_{5} ⟶ A a l c o h o l i c - ---- \to K O H B

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