For the series of competitive reactions: H+HO2K1−→H2+O2 H+HO2K2−→2OH H+HO2K3−→H2O+O It has been found that K1:K2:K3=0.60:0.30:0.10. The molar ratio of the product, H2,O2,OH,H2O and O, at time t, is:
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Solution
(1) From the equations molar ratio of H2 & H is 1H21moleH .
(1) From the equations molar ratio ofH2 and HO2 is 1molesH21molHO2 .
(1) From the equations molar ratio ofO2 & H=1molO21molH .
(1) From the equations molar ratio ofO2 & HO2=1molO21molHO2 .
(2) From the equations molar ratio ofOH & H=2molOH1molH .
(2) From the equations molar ratio ofOH & O2H=2molOH1molO2H .
(3) From the equations molar ratio ofH2O & H=1molH2O1molH .
(3) From the equations molar ratio ofH2O & HO2=1molH2O1molHO2 .
(3) From the equations molar ratio ofO & HO2=2molO1molHO2 .