For the shown system of fixed charges, at what distance from 9 nC will electric field due to system of charges be zero.
A
0.67m from 9nC charge towards left
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B
1m from 9nC charge towards left
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C
0.27m from 9nC charge towards left
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D
2.7m from 9nC charge towards left
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Solution
The correct option is B1m from 9nC charge towards left We know that the third charge should be placed on the line joining the two charges and near the smaller charge towards left.
Distance of third charge from charge of smaller magnitude is given by x=[√q1√q2−√q1]L,
where q1 is magnitude of 9nC charge and q2 magnitude of −36nC charge ⇒x=[√9√36−√9]×1 ⇒x=1m