For the shown system of fixed charges, where should a third charge of 3nC be placed, so that the system remains in equilibrium.
A
0.57m from 4nC charge toward left
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B
0.37m from 4nC charge toward left
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C
0.67m from 4nC charge toward left
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D
0.47m from 4nC charge toward left
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Solution
The correct option is C0.67m from 4nC charge toward left We know that the third charge should be placed on the line joining the two charges and near the smaller charge towards left.
Distance of third charge from charge of smaller magnitude is given by x=[√q1√q2−√q1]L,
where q1 is magnitude of 4nC charge and q2 magnitude of −25nC charge ⇒x=[√4√25−√4]×1 ⇒x=0.67m