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Standard VII

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Marathas

For the speci...

Question

For the specimen shown in figure, if the rate of flow is $2 c m^{3} / m i n$ and area of cross section in $8 c m^{2}$ , soil permeability (in cm/s) is

5 \times 10^{- 4}

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3.5 \times 10^{- 3}

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5 \times 10^{- 3}

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0.3

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Solution

The correct option is C $5 \times 10^{- 3}$
$Δ h$ = head difference = 15 - 05 = 10 cm

L = Drainage length = 12 cm
A= Cross section area $= 8 c m^{2}$

q= k i A as per Darcy's law

$\Rightarrow 2 c m^{3} / m i n = k i A$

$\Rightarrow (\frac{2}{60}) c m^{3} / s = k \frac{Δ h}{L} A$

$\Rightarrow k = \frac{2}{60} \times \frac{12}{10} \times \frac{1}{8} = 5 \times 10^{- 3} c m / s$

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For the specimen shown in figure, if the rate of flow is 2 cm3/min and area of cross section in 8 cm2, soil permeability (in cm/s) is

The correct option is C 5×10−3Δh = head difference = 15 - 05 = 10 cm L = Drainage length = 12 cm A= Cross section area =8 cm2 q= k i A as per Darcy's law ⇒2 cm3/min=k i A ⇒(260)cm3/s=kΔhLA ⇒k=260×1210×18=5×10−3cm/s

For the specimen shown in figure, if the rate of flow is $2 c m^{3} / m i n$ and area of cross section in $8 c m^{2}$ , soil permeability (in cm/s) is