CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Strength of Materials

Plane of Maximum Shear Stress

For the state...

Question

For the state of stress (in MPa) shown in the figure below the maximum shear stress (in MPa) is

5

Open in App

Solution

The correct option is A 5
Radius of Mohr circle = max. shear stress
$R = \sqrt{(4 - 1)^{2} + (- 4 - 0)^{2}}$
$R = \sqrt{(4 - 1)^{2} + (4)^{2}}$
$R = 5$
$τ_{m a x} = 5$

Suggest Corrections

thumbs-up

0

Similar questions

Q. For the stress state (in MPa) shown in the figure, the major principal stress is 10 MPa.

The shear stress

τ

Q. For a state of plane stress

σ_{1} = σ_{x} = 40 M P a a n d σ_{2} = σ_{y} M P a

. What are the values of the maximum in-plane shearing stress and absolute maximum shearing stress?

Q. The state of plane-stress at a point is given by

σ_{x} = 200 M P a

σ_{y} = 100 M P a

τ_{x y} = 100 M P a

. The maximum shear stress (in MPa) is

Q. If the principal stresses in a plane stress problem are

σ_{1} = 100

σ_{2} = 40

MPa, the magnitude of the maximum shear stress (in MPa) will be

Q. In a plane stress condition, the components of stress at a point are

σ_{x} = 20

σ_{y} = 80

τ_{x y} = 40

MPa. The maximum shear stress (in MPa) at the point is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Plane of Maximum Shear Stress

STRENGTH OF MATERIALS

Watch in App

explore_more_icon

Explore more

Plane of Maximum Shear Stress

Other Strength of Materials

Join BYJU'S Learning Program

CrossIcon