Question

For the stationary wave $y=4sin\left(\frac{\pi x}{15}\right)cos\left(96\pi t\right)$, the distance between a node and the next antinode is

• A. 7.5
• B. 15
• C. 22.5
• D. 30

Answer 1

The correct option is A 7.5

On comparing given equation with standard equation, we get

$\frac{2\pi }{\lambda }=\frac{\pi }{15}$

$\Rightarrow \lambda =30$

Distance between the node and antinode

$=\frac{\lambda }{4}$

$=\frac{30}{4}=7.5$