For the system 3A + 2B ⇌ C, the expression for equilibrium constant is
([3A][2B])/[C]
[C]/([3A][2B])
([A]3[B]2)/[C]
[C]/([A]3[B]2)
Equilibrium constant for the reaction, 3A + 2B ⇌ C is
K = [C][A]3[B]2
For the reaction A+2B ⇌ C, the expression for equilibrium constant is
Question 5(d) Substract: 3a(a+b+c)−2b(a−b+c)from 4c(−a+b+c).