Question

For the system $A\left(g\right)+2B\left(g\right)\rightleftharpoons C\left(g\right)$, the equilibrium concentration for $A,B$ and $C$ (in $moles/litre$) are $0.06,0.12$ and $0.216$ respectively.The $K_{eq}$ for the reaction is

• A. $250$
• B. $416$
• C. $4\times {10}^{-3}$
• D. $125$

Answer 1

The correct option is A $250$

$K\left(eq\right)=\frac{\left(c\right)}{\left(\right(a)\times (b^2\left)\right)}$

=$\frac{0.216}{0.06\times {0.12}^2}$

=$\frac{0.216}{0.06\ast 0.0144}$

=$\frac{0.216}{0.000864}$

=$\frac{216\times {10}^{-3}}{864\times {10}^{-6}}$

=250

Hence A is correct option