Question

For the system A(g) + 2B(g) $\rightleftharpoons$​ C(g), the equilibrium concentrations are (A)

0.06 mole/litre (B) 0.12 mole/litre (C) 0.216 mole/litre. The $K_{eq}$ for the

reaction is

• A. 250
• B. 416
• C. 4 x 10^-3
• D. 125

Answer 1

The correct option is A

250

For reaction $A+2B$ $\rightleftharpoons$$C$

$K$ = $\frac{\left[C\right]}{\left[A\right][B{]}^2}=\frac{0.216}{0.06\times 0.12\times 0.12}$ = $250$