The correct option is A 1.75 (ACF)Rx(t)CTFT→Sx(t)(PSD)sinc(2t)CTFT→12rect(f2)4sinc2(2t)CTFT→[rect(f2)rect(f2)]cos(2πt)CTFT→12[δ(f−1)+δ(f+1)] Fortimeaveragepowers,Sz(f)=14[SX(f−1)+SX(f+1)] AfterpassingthroughanLPFwithfc=2Hz,weget, Py∫∞−∞Sy(f)df=2[(1×0.50)+(1×0.25)+(12×1×0.25)]W=1.75W