wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the system shown in the figure, if F2 and F3 are forces acting on the masses m2 and m3 respectively, then the correct relation between the forces is (Assume that the blocks are connected by inextensible strings and the surface is frictionless)

A
F3=F1+F2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
F3=m1F1m1+m2+m3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
F3=m2F1m1+m2+m3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
F3=m3F1m1+m2+m3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D F3=m3F1m1+m2+m3
Assuming the connecting strings are inextensible, the whole system will move with common acceleration a. Therefore we can draw FBD of the blocks, treating it as one system​​​​​​.

F1=(m1+m2+m3)a
a=F1m1+m2+m3

Now, draw the FBD of mass m3 alone


F3=m3a(1)

Substituting a in equation (1), we get
F3=m3F1m1+m2+m3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What's with All the Tension in the Room?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon