For the system shown in the figure, the pulley is smooth and massless, the string is massless and inextensible. If the acceleration of the system is (a) then, find out the ratio of tensions T1 and T2. (Take g=10m/s2)
A
20:3
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B
5:1
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C
3:1
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D
5:2
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Solution
The correct option is C3:1
Here, net pulling force will be (weight of 4kg and 2 kg blocks on one side)− (weight of 4kg block on the other side ). Acceleration of the system is given by a; ∴a=Net pulling forceTotal mass
⇒a=(2×10)+(4×10)−(4×10)2+4+4
∴a=2010=2 m/s2
For T1: From FBD of 4kg block, T1−40=4a T1=40+4a T1=40+(4×2)=48N