For the $t_{2 g}^{6} e_{g}^{2}$ system, the value of magnetic moment $(μ)$ is:

2.83 B M

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1.73 B M

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3.87 B M

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4.92 B M

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Solution

The correct option is C $2.83 B M$

$M = \sqrt{n (n + 2)}$

where, n= no. of unpaired $e^{-}$

Here, $n = 2$

$∴ M = \sqrt{2 (2 + 2)}$

$\Rightarrow \sqrt{8} = 2.82 B M$

Hence, option A is correct.

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