Question

For the thermodynamic cycle shown in figure, find the net output work of the gas during the cycle :

• A. $2.5J$
• B. $1.5J$
• C. $0.5J$
• D. $0.75J$

Answer 1

Answer: (C)

$0.5J$

Area enclosed under the P-V graph gives the net work done by the gas during the cyclic process.

From the graph, $AD=(4-2)\times {10}^5=2\times {10}^{5}Pa$

Also $CD=4-1.5=2.5c{m}^3=2.5\times {10}^{-6}{m}^3$

$\therefore$ Net output work $W=AD\times CD=2\times {10}^5\times 2.5\times {10}^{-6}=0.5J$