For the transformer shown in figure if the primary to secondary turns ratio is 1 : 10, the voltage across the terminals of the secondary coil-will be :

Zero

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1

volt

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10

volt

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100

volt

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Solution

The correct option is D $100$ volt
For a transformer we know the relation $= \frac{N_{1}}{N_{2}} = \frac{V_{1}}{V_{2}}$
where N1 = no. of bindings in primary coil
N2 = no. of bindings in secondary coil
V1 = voltage of primary coil
V2 = voltage of secondary coil
$= \frac{1}{10} = \frac{10}{V_{2}}$
$= V_{2} = 100 v o l t$

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For the transformer shown in figure if the primary to secondary turns ratio is 1 : 10, the voltage across the terminals of the secondary coil-will be :

The correct option is D 100 voltFor a transformer we know the relation =N1N2=V1V2 where N1 = no. of bindings in primary coil N2 = no. of bindings in secondary coil V1 = voltage of primary coil V2 = voltage of secondary coil=110=10V2=V2=100volt