For the transistor circuit shown, β=100 and voltage drop between emitter and base is 0.7V. The value of VCE will be
A
10V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
13V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C13V Let us redraw the circuit diagram to denote the potential at different points and the current through different segments.
Here ic is the collector current while ib is the base current. Also we have assumed that potential at points A and B is 0. The net potential drop across any loop must be zero. Writing the voltage equation for the loop consisting of the resistance of 8.6kΩ 5−8.6×103×ib−0.7=0 ---(1) Also, β=icib=100 ---(2) Writing the balance equation for the loop consisting of the resistance of 100Ω 18−100×ic−VCE=0 -----------(3)
From equation (1), ib=0.5×10−3A From equation (2), ic=0.05A and from equation (3), VCE=13V