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Question

# For the transistor circuit shown, β=100 and voltage drop between emitter and base is 0.7 V. The value of VCE will be

A
10 V
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B
5 V
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C
13 V
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D
0 V
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Solution

## The correct option is C 13 VLet us redraw the circuit diagram to denote the potential at different points and the current through different segments. Here ic is the collector current while ib is the base current. Also we have assumed that potential at points A and B is 0. The net potential drop across any loop must be zero. Writing the voltage equation for the loop consisting of the resistance of 8.6 kΩ 5−8.6×103×ib−0.7=0 ---(1) Also, β=icib=100 ---(2) Writing the balance equation for the loop consisting of the resistance of 100 Ω 18−100×ic−VCE=0 -----------(3) From equation (1), ib=0.5×10−3 A From equation (2), ic=0.05 A and from equation (3), VCE=13 V

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