Question

For the trial slip circle shown in Figure, Calculate the factor of safety. [Data: weight of the soil = 346 KN/m, unit weight of the soil = $19KN/m^3,$ $C_u=20KN/m^2]$

• A. 1.14

Answer 1

The correct option is A 1.14
We know that,

FOS = $\frac{Resistingmoment}{Actuatingmoment}$

= $\frac{C\times l\times r}{W\times 5}...\left(i\right)$

Angle = $\frac{Arc}{Radius}$

$70\times \frac{\pi }{{180}^{\circ }}=\frac{l}{9}$

l = 10.995 m

From(i)

FOS = $\frac{20\times 10.995\times 9}{346\times 5}$

FOS = 1.14