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Byju's Answer
Standard XII
Mathematics
Collinear Vectors
For the vecto...
Question
For the vectors
→
A
and
→
B
shown in figure, if A=15 N, B= 15 N, then
|
→
A
−
→
B
|
=
?
A
15
N
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B
15
√
3
N
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C
30
N
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D
15
√
3
N
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Solution
The correct option is
A
15
N
We know,
When
|
A
|
,
|
B
|
are equal, and
=
|
A
|
|
A
+
B
|
=
2
|
A
|
cos
θ
2
|
A
−
B
|
=
2
|
A
|
sin
θ
2
Here,
|
A
−
B
|
=
2
×
15
×
sin
(
30
0
)
|
A
−
B
|
=
15
Option
A
is the correct answer
Suggest Corrections
0
Similar questions
Q.
A
and
B
are sets such that
n
(
A
) = 15 and
n
(
B
) = 25 and
n
(
A
∪
B
) = 30, then
n
(
A
∩
B
) =
A
तथा
B
समुच्चय हैं जबकि
n
(
A
) = 15 और
n
(
B
) = 25 तथा
n
(
A
∪
B
) = 30, तब
n
(
A
∩
B
) =
Q.
If
n
(
ξ
)
=
30
,
n
(
A
)
=
22
,
n
(
B
)
=
15
and
n
(
A
∪
B
)
=
25
, then find :
n
(
B
′
)
.
Q.
If
n
(
ξ
)
=
30
,
n
(
A
)
=
22
,
n
(
B
)
=
15
and
n
(
A
∪
B
)
=
25
, then find :
n
(
A
′
).
Q.
If
n
(
ξ
)
=
30
,
n
(
A
)
=
22
,
n
(
B
)
=
15
and
n
(
A
∪
B
)
=
25
, then find :
n
(
A
∩
B
′
)
Q.
Find the value of
n
:
3
(
n
−
5
)
+
5
n
=
7
(
a
−
n
)
−
2
(
n
−
b
)
, where
a
and
b
are constants.
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