Question

For the velocity time graph shown in the figure, the distance covered by the body in the last two seconds of its motion is what fraction of the total distance travelled by it in all the seven seconds?

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{2}{3}$
• D. $\frac{1}{3}$

Answer 1

Answer: (B)

$\frac{1}{4}$

Distance covered is equal to the area under velocity-time graph.

Distance in last two seconds $s_2=\frac{1}{2}\times 8\times 2=8m$
Total distance $=\frac{1}{2}\times 8\times (6+2)=32m$

Fraction of the distance covered by the body in the last two seconds of its motion to total distance traveled by it in all the seven seconds is $8/32=1:4$