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Enthalpy of Solution

For the water...

Question

For the water gas reaction
$C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} O (g)$
the standard Gibbs free energy of reaction (at $1000 K$ ) is $- 8.1 k J / m o l$ . Calculate its equilibrium constant.

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Solution

We know that
$K = a n t i log (\frac{Δ G^{o}}{2.303 R T}) . . . (i)$
Given that, $Δ G^{o} = - 81. k J / m o l, R = 8.314 \times 10^{- 3} k J K^{- 1} {m o l}^{- 1}, T = 1000 K$
Substituting these values in eq. (i) we get
$K = a n t i log (\frac{- (- 8.1)}{2.303 \times 8.314 \times 10^{- 3} \times 1000}) = 2.65$

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