For the water gas reaction, C(s)+H2O(g)⇌CO(g)+H2(g) the standard Gibbs free energy of reaction (at 1000K) is −8.1kJ/mol. Calculate its equilibrium constant
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Solution
We know that, K=antilog(−△G∘2.303RT)...(1) Given, △G∘=−8.1kJ/mol R=8.314×10−3kJK−1mol−1 T=1000K Substituting the values in equation (1), we get K=antilog[−(−8.1)2.303×8.314×10−3×1000] K=2.65