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Question

For the water gas reaction,
C(s)+H2O(g)CO(g)+H2(g)
the standard Gibbs free energy of reaction (at 1000 K) is 8.1 kJ/mol. Calculate its equilibrium constant

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Solution

We know that,
K=antilog(G2.303RT) ...(1)
Given, G=8.1 kJ/mol
R=8.314×103 kJ K1 mol1
T=1000 K
Substituting the values in equation (1), we get
K=antilog[(8.1)2.303×8.314×103×1000]
K=2.65

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