Question

For three gases $A,B$ and $C$, the values of their critical temperatures $\left(T_C\right)$ are such that
$T_C\left(A\right)>T_C\left(B\right)>T_C\left(C\right)$
assuming identical value of '$b$'. Which gas can be most easily liquefied?

• A. $A$
• B. $B$
• C. $C$
• D. All at same temperature

Answer 1

Answer: (A)

$A$

Higher is the value of critical temperature, higher is the ease of liquefaction.
$T_c=\frac{8a}{27Rb}$

$T_c\propto a$

The critical temperature is the highest temperature at which the gaseous state starts condensation into a liquid state.

As the $T_c$ of A is highest, therefore, it is liquefied easily.

Gas $A$ can be most easily liquefied as it has a maximum value of critical temperature.

Hence, the correct answer is option $\text{A}$.