For three sets A, B and C, show that
(i) A∩B=A∩C need not imply B = C.
(ii) A⊂B⇒C−B⊂C−A
(i) Let A = {1,2,3}, B = {2,4,6} and C = {2,5,7}
Then
A∩B ={2}
and A∩B ={2}
Hence, A∩B=A∩C, but clearly B ≠ C.
(ii) Given A⊂B
To show: C- B ⊂ C - A
Let x ϵC−B
⇒x ϵ C and x /ϵB [∴ By definition of C- B]
⇒x ϵ C and /ϵ A [∴A⊂B]
This can be seen by the venn diagram above
⇒x ϵ C−A [by definition of C- A]
Thus x ϵ C−B⇒x ϵ C−A. This is true for all x ϵC−B
∴C−B⊂C−A