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Question

For three sets A, B and C, show that

(i) AB=AC need not imply B = C.

(ii) ABCBCA

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Solution

(i) Let A = {1,2,3}, B = {2,4,6} and C = {2,5,7}

Then

AB ={2}

and AB ={2}

Hence, AB=AC, but clearly B C.

(ii) Given AB

To show: C- B C - A

Let x ϵCB

x ϵ C and x /ϵB [ By definition of C- B]

x ϵ C and /ϵ A [AB]

This can be seen by the venn diagram above

x ϵ CA [by definition of C- A]

Thus x ϵ CBx ϵ CA. This is true for all x ϵCB

CBCA


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