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B
B∩C
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C
B∪C
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Solution
The correct option is AA Given three sets A,B&C and A⊂B⇒A∩B=A;A∪B=B
Similarly, A⊂C⇒A∩C=A;A∪C=C
Now, by distributive property: A∩(B∪C)=(A∩B)∪(A∩C) ⇒A∩(B∪C)=A∩A=A