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Question

For three vectors a,b and c if a×b=c and a×c=b,then prove that a,b and c are mutually perpendicular vectors,|b|=|a| and |a|=1

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Solution

We are given that
a×b=cac and bca×c=cab and cb}abc....(i)Now,a×b=c|a×b|=|c||a||b|sin π2=|c||a||b|=|c|...(ii) [by (i),abAnd,a×c=b|a||c|sin π2=|b||a||c|=|b|...(iii) [by (i),acBy (ii)÷(iii),we get:|c|2=|b|2|c|=|b|.Substitute |c|=|b| in (ii) to obtain,|a|=1.

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