Question

For titration of $1.0$M $H_{2}S{O}_4$ solution against $50$ milliliters of $1.0$M $NaOH$ solution, what volume of $H_{2}S{O}_4$ in milliliters will be required for neutralization?

• A. $10.$
• B. $25$.
• C. $40$.
• D. $50$.
• E. $100$.

Answer 1

The correct option is B $25$.

$H_{2}S{O}_4+2NaOH\to N{a}_{2}S{O}_4+2H_{2}O$
Number of moles of NaOH $=2\times$ number of moles of $H_{2}S{O}_4$
$M_{1}V1=M_{2}V2$
$M_1=1.0$ M $=$ molarity of NaOH
$M_2=1.0$ M $=$ molarity of $H_{2}S{O}_4$
$V_1=50$ mL $=$ volume of NaOH
$V_2=$ volume of $H_{2}S{O}_4$
$1.0\times 50=2\times 1.0\times V_2$
$V_2=25$mL