For total internal reflection to take place, the angle of incidence $i$ and the refractive index $μ$ of the medium must satisfy the inequality

\frac{1}{s i n i} < μ

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\frac{1}{s i n i} > μ

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s i n i

μ

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s i n i

μ

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Solution

The correct option is C $\frac{1}{s i n i} < μ$
For total internal reflection, the angle of incidence $i$ must be greater than critical angle.
So, $s i n i > \frac{1}{μ}$
$\Rightarrow \frac{1}{s i n i} < μ$

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For total internal reflection to take place, the angle of incidence i and the refractive index μ of the medium must satisfy the inequality

The correct option is C 1sini<μFor total internal reflection, the angle of incidence i must be greater than critical angle.So, sini>1μ⇒1sini<μ

For total internal reflection to take place, the angle of incidence $i$ and the refractive index $μ$ of the medium must satisfy the inequality

The correct option is C $\frac{1}{s i n i} < μ$
For total internal reflection, the angle of incidence $i$ must be greater than critical angle.
So, $s i n i > \frac{1}{μ}$
$\Rightarrow \frac{1}{s i n i} < μ$