For triangle ABC, R=5/2 and r=1. Let I be the incenter of the triangle and D,E and F be the feet of the perpendiculars from I to BC, CA and AB, respectively. The value of ID×IE×IFIA×IB×IC is equal to ?
A
52
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B
54
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C
110
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D
15
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Solution
The correct option is C110 From the figure, IDIC=sinC2