For two position of lens, the images are obtained on a fixed screen. If the size of the object is 2 cm and size of diminished image is 0.5 cm, the size of the other image will be

1 cm

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4 cm

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8 cm

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16 cm

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Solution

The correct option is B 8 cm
$h e i g h t_{o b j e c t}^{2} = h e i g h t_{i m a g e 1} \times h e i g h t_{i m a g e 2}$

$2 \times 2 = 0.5 \times h$

$h = 8$

option $C$ is correct

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