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Question

For two triangles PQR and XYZ, PQQR=YZZX and QRPR=ZXYX .

A
∆PQR~ ∆YZX
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B
∆RPQ ~ ∆YZX
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C
∆PQR~∆XYZ
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Solution

The correct option is A ∆PQR~ ∆YZX

PQQR=YZZX

PQYZ=QRZX ----------- I

QRPR=ZXYX

QRZX=PRYX -----------II

From I and II,

PQYZ=QRZX=PRYX

PQRYZX by SSS axiom.


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