Question

For van der Waals' constants ${}^{\prime }{a}^{\prime }$ and ${}^{\prime }{b}^{\prime }$, the unit of the ratio $\frac{a}{b}$ will be:

• A. $atmlitr{e}^{-1}$
• B. $litre-atmmo{l}^{-1}$
• C. $litre-atmmo{l}^{-2}$
• D. $litremo{l}^{-1}$

Answer 1

The correct option is B $litre-atmmo{l}^{-1}$

$P_{correction}=\frac{a{n}^2}{V^2}$

Unit of $a=atmlitr{e}^{2}mo{l}^{-2}$
$V_{correction}=nb$

Unit of $b=litremo{l}^{-1}$
Unit of $\left(\frac{a}{b}\right)=\frac{atmlitr{e}^{2}mo{l}^{-2}}{litremo{l}^{-1}}$
$=atmlitremo{l}^{-1}$