For vectors →A and →B making an angle θ which one of the following relations is correct?
A
→A×→B=→B×→A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
→A×→B=ABsinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
→A×→B=ABcosθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
→A×→B=−→B×→A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D→A×→B=−→B×→A If θ be the angle between two vectors →A and →B, the cross product will be →A×→B=AB^nsinθ and dot product will be →A.→B=ABcosθ where ^n is the normal vector to →A and →B
The one of the property of cross product is anti-commutative, i.e. →A×→B=−→B×→A