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Question

For vectors A and B making an angle θ which one of the following relations is correct?

A
A×B=B×A
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B
A×B=ABsinθ
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C
A×B=ABcosθ
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D
A×B=B×A
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Solution

The correct option is D A×B=B×A
If θ be the angle between two vectors A and B, the cross product will be A×B=AB^nsinθ and dot product will be A.B=ABcosθ where ^n is the normal vector to A and B
The one of the property of cross product is anti-commutative, i.e. A×B=B×A

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