For verification of Ohm's law, the data obtained are given below :
V (in volt) 0.2 0.4 0.6 0.8 1.0 1.2
I (in ampere)
0.5 1.0 1.5 2.0 2.5 3.0
Plot graph for V against I.
Use graph to find $I_{1}$ at $V_{1} = 0.3$ volt and $I_{2} a t V_{2} = 1.1$ volt.
Then find the slope $\frac{V_{2} - V_{1}}{I_{2} - I_{1}}$ .

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Solution

$\frac{V_{2} - V_{1}}{I_{2} - I_{1}} = \frac{1.1 - 0.3}{2.7 - 0.7} = 0.4 v o l t / a m p e r e$

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Similar questions

Q. An experiment is performed to verify Ohm's law. Observations are tabulated as follows:

\begin{matrix} C u r r e n t (I) i n a m p e r e s & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 P o t e n t i a l d i f f e r e n c e (V) i n v o l t s & 1.2 & 2.4 & 3.6 & 4.8 & 6.0 \end{matrix}

(a) From the data, plot a V-I graph.
(b) Show that the graph confirms the Ohm's law.
(c) Find the resistance of the resistor used.
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Q. A student using the same two resistors, ammeter, voltmeter and battery, sets up two circuits A and B connecting the two resistors first in series and then in parallel.

If the ammeter and voltmeter readings in the two cases be I₁, I₂ and V₁, V₂ respectively he is likely to observe that :
(1) I₁ = I₂ but V₁ ≠ V₂
(2) I₁ < I₂ but V₁ = V₂
(3) I₁ > I₂ but V₁ = V₂
(4) I₁ = I₂ and V₁ = V₂

In an experiment of verification of Ohm's law, following observations are obtained.
$\begin{matrix} Potential difference V (in Volt) & 0.5 & 1.0 & 1.5 & 2.0 & 2.5 Current I (in ampere) & 0.2 & 0.4 & 0.6 & 0.8 & 1.0 \end{matrix}$
Draw a V- I graph and use this graph to find :
(a) the potential difference V when the current I is 0.5 A,
(b) the current I when the potential difference V is 0.75 V,
(c) the resistance in circuit.

(a) Draw a V-I graph for a conductor obeying Ohm's law.

(b) What does the slope of V-I graph for a conductor represent?

Q. For three circuits, shown here

the same two resistors R₁ and R₂ have been connected in parallel in all the circuits but the voltmeter and the ammeter have been connected in three different positions. The relation between the three voltmeter and ammeter readings would be :
(1) V₁ = V₂ = V₃ and I₁ = I₂ = I₃
(2) V₁ ≠ V₂ ≠ V₃ and I₁ = I₂ = I₃
(3) V₁ = V₂ = V₃ and I₁ ≠ I₂ ≠ I₃
(4) V₁ ≠ V₂ ≠ V₃ and I₁ ≠ I₂ ≠ I₃

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V (in volt)	0.2	0.4	0.6	0.8	1.0	1.2
I (in ampere)	0.5	1.0	1.5	2.0	2.5	3.0

For verification of Ohm's law, the data obtained are given below :V (in volt)0.20.40.60.81.01.2I (in ampere)0.51.01.52.02.53.0Plot graph for V against I. Use graph to find I1 at V1=0.3 volt and I2atV2=1.1 volt. Then find the slope V2−V1I2−I1.

V2−V1I2−I1=1.1−0.32.7−0.7=0.4volt/ampere

$\frac{V_{2} - V_{1}}{I_{2} - I_{1}} = \frac{1.1 - 0.3}{2.7 - 0.7} = 0.4 v o l t / a m p e r e$