Question

For wave connected with proton, de-broglie wavelength change by 0.25% if its momentum change by $P_0$ initial momentum=

• A. $100P_0$
• B. $\frac{P_0}{400}$
• C. $401P_0$
• D. $\frac{P_0}{100}$

Answer 1

Answer: (C)

$401P_0$

Using,

$\lambda =\frac{h}{p}$ where $\lambda =$ wavelength

$p=$ Momentum

While Reducing wavelength by $0.25$% then momentum reduces by $1$ unit.

So, $(1-0.5\lambda )=\frac{h}{p}$

Initial Momentum $=$ $401p_0$