For what each time value of n in this expression 3^4n -4^3n is exactly divisible by 17

Open in App

Solution

3^4n - 4^3n
put n =1
3^4 -4^3 = 81-64=17

now put n=2
3^8-4^6 =6561-4096= 2465 =17*145

similarly for all n= 1 2 3 .. .....
it is divisible by 17

Suggest Corrections

Similar questions

3^{4 n} - 4^{3 n}

10^{n} + 3 \cdot 4^{n + 2} + λ

9

n \in N

λ

\forall n \in N, 4^{n} - 3 n - 1

1. (x - ω) (2 - ω^{2}) + 2. (3 - ω) (3 - ω^{2}) + . . . . . . . . . + (n - 1) . (n - ω) (n - ω^{2})

ω

1. (2 - w) (2 - w^{2}) + 2. (3 - w) (3 - w^{2}) + . . . . . . . . . . + (n - 1) (n - w) (n - w^{2}),

Join BYJU'S Learning Program

Select...