For what least value of 'n' a natural number, $(24)^{n}$ is divisible by $8$ ?

Open in App

Solution

Let $n = 1$ in ${(24)}^{n}$
We have $,$
$24,$ which is divisible by $8.$
Hence the least number is $1.$

Suggest Corrections

Similar questions

3^{2 n + 2} - 8 n - 9

If n is a natural number then 8^n - 3^n is divisible by which number?

n

n

5^{n} + 4^{n}

9

$5^{2 n + 2} - 24 n - 25$ is divisible by 576 for all n $ϵ$ N.

n, 3^{2 n + 2} - 8 n - 1

8

Join BYJU'S Learning Program