Question

For what point of the parabola $y^2=14x$ is the ordinate equal to twice the abscissa.

Answer 1

$y=2x$ ...(1)

as ordinate is y intercept and

abscissa is x intercept

$y^2=14x$ ...(2)

From (1) and (2)

$(2x{)}^2=14x$

$4x^2=14x$

$x=0,x=\frac{7}{2}$

When $x=\frac{7}{2},y=7$ so $(\frac{7}{2},7)$