For what value of 'k' are the following points (7,-2), (5, 1), (3, k) collinear ?
4
Let A(7,−2), B(5,1) & C(3,k) be the vertices of a triangle.
Condition for collinear points, ar(△ABC)=0
Area of triangle having coordinates (x1,y1), (x2,y2), (x3,y3) is
12×|x1(y2−y3)+x2(y3−y1)+x3(y1−y2)|
∴12|7(1−k)+5(k+2)+3(−2−1)|=07−7k+5k+10+(−6)−3=017−9+5k−7k=08−2k=0⇒2k=8⇒k=82∴k=4