Question

For what value of k is (-2) a zero of the polynomial $x^2-x-(2k+2)?$

• A. 1
• B. 2
• C. - 1
• D. - 2

Answer 1

The correct option is B 2

Given that (-2) is a zero of $f\left(x\right)=x^2-x-(2k+2),$ we have f(-2) = 0.
$\Rightarrow (-2{)}^2-(-2)-(2k+2)=0$
$\Rightarrow 4+2-2k-2=0$
$\Rightarrow k=2$