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nth Term of A.P

For what valu...

Question

For what value of 'k', k-3, 2k+1 and 4k+3 are in A.P.?

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Solution

$k - 3; 2 k + 1, 4 k + 3 are in AP$

$t h e n (2 k + 1) - (k - 3) = (4 k + 3) - (2 k + 1)$

$\Rightarrow k + 4 = 2 k + 2$

$\Rightarrow k = 2$

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