Question

for what value of k ,x = 2 , y=3 is a solution of the equation (k+1)x - (2k + 3)y-1 = 0

Answer 1

$$\begin{gathered} \mathrm{The}\mathrm{given}\mathrm{equation}\mathrm{is}, \\ \left(\mathrm{k}+1\right)\mathrm{x}-\left(2\mathrm{k}+3\right)\mathrm{y}-1=0 \\ \mathrm{Put}\mathrm{x}=2\mathrm{and}\mathrm{y}=3\mathrm{in}\mathrm{the}\mathrm{above}\mathrm{equation},\mathrm{we}\mathrm{get} \\ \left(\mathrm{k}+1\right)\times 2-\left(2\mathrm{k}+3\right)\left(3\right)-1=0 \\ \Rightarrow 2\mathrm{k}+2-6\mathrm{k}-9-1=0 \\ \Rightarrow -4\mathrm{k}-8=0 \\ \Rightarrow -4\mathrm{k}=8 \\ \Rightarrow \mathrm{k}=-2 \end{gathered}$$