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Question

For what value of m is x3 2mx2+16 is divisible by x + 2?

A

0
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B

1
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C

2
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D

3
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Solution

The correct option is B
1
Let p(x)=x32mx2+16
Since, p(x) is divisible by (x+2), the remainder = 0
p(2)=0 [ by remainder theorem]
(2)32m(2)2+16=0
88m+16=0
8=8m
m=1.
Hence, the value of m is 1.

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