For what value of m, the system of equations mx + 3y = m – 3 , 12x + my = m will have no solution
-4
4
-6
6
m12 = 3m ≠ −(m−3)−m
⇒ m2=36
⇒ m = ±6 --------(1)
⇒ 3m ≠ m(m-3)
⇒ 3m≠ m2−3m
⇒ m(m−6)≠ 0
⇒ m ≠ 0 and 6 -------(2)
So, from (1) and (2) m = -6
Find the value of k for which each of the following systems of equations has no solution:
kx+3y=3,12x+ky=6.