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Question

Question 15
For what value of n, are the nth terms of two APs 63, 65, 67, and 3, 10, 17, … equal?

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Solution

63,65,67,a=63d=a2a1=6563=2nth term of this A.P,an=a+(n1)dan=63+(n1)2=63+2n2an=61+2n(i)3,10,17a=3d=a2a1=103=7nth term of this A.P=3+(n1)7an=3+7n7an=7n4(ii)
It is given that, nth term of these A.Ps are equal to each other.
Equating both these equations, we obtain,
61 + 2n = 7n - 4
61 + 4 = 5n
5n = 65
n = 13
Therefore, 13th
terms of both these A.Ps are equal to each other.

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