For what value of n- a2 n-1-b2 n-1-a2 n-b2 n is the arithmetic mean of a and b where a-b-

The correct option is B 02(a^2n+1+b^2n+1/a^2n+b^2n) = a+b nbsp; Solving this, we get a^2n(a b)=b^2n(a b) → (a/b)^2n=1 → n=0 ...

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Solving a Quadratic Equation by Completion of Squares Method

For what valu...

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For what value of $n, \frac{a^{2 n + 1} + b^{2 n + 1}}{a^{2 n} + b^{2 n}}$ is the arithmetic mean of a and b where $a \neq b$ .

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n \in N

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\frac{{sin}^{4 n} θ}{a^{2 n - 1}} + \frac{{cos}^{4 n} θ}{b^{2 n - 1}} = \frac{1}{{(a + b)}^{2 n - 1}}, n \in N

\frac{{sin}^{4} x}{a} + \frac{{cos}^{4} x}{b} = \frac{1}{a + b}

\frac{{sin}^{8} x}{a^{3}} + \frac{{cos}^{8} x}{b^{3}} = \frac{1}{{(a + b)}^{3}}

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\frac{b^{2 n + 2} - a^{2 n + 2}}{a b (b^{2 n} - a^{2 n})} = \frac{n + 1}{n} .

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